Thực hiện phép chia (15x^4 + 4x^3 + 11x^2 + 14x – 8) : (5x^2 + 3x – 2)

* Hướng dẫn giải

$\begin{array}{l}15x^4+4x^3+11x^2+14x-8\overline{)5x^2+3x-2}\\ 15x^4+9x^3-6x^{2}3x^2-x+4\\ \overline{-5x^3+17x^2+14x-8}\\ -5x^3-3x^2+2x\\ \overline{\begin{array}{l}20x^2+12x-8\\ 20x^2+12x-8\\ \overline{0}\end{array}}\end{array}$

Vậy $\left(15x^4+4x^3+11x^2+14x-8\right):\left(5x^2+3x-2\right)=3x^2-x+4$