Thực hiện phép tính sau: (2x^3 −3x^2 +6x −9) : (2x−3)

* Hướng dẫn giải

$\begin{array}{l}\left(2x^3-3x^2+6x-9\right):\left(2x-3\right)=\left[\left(2x^3-3x^2\right)+\left(6x-9\right)\right]:\left(2x-3\right)\\ =\left[x^2\left(2x-3\right)+3\left(2x-3\right)\right]:\left(2x-3\right)\\ =\left(x^2+3\right)\left(2x-3\right):\left(2x-3\right)\\ =x^2+3\end{array}$