Tìm x, biết rằng: 8x (x−5) −2x +10 =0

* Hướng dẫn giải

$\begin{array}{l}8x\left(x-5\right)-2x+10=0\\ 8x\left(x-5\right)-\left(2x-10\right)=0\\ 8x\left(x-5\right)-2\left(x-5\right)=0\\ \left(8x-2\right)\left(x-5\right)=0\\ \Rightarrow \left[\begin{array}{l}8x-2=0\\ x-5=0\end{array}\right.\\ \Rightarrow \left[\begin{array}{l}x=\frac{1}{4}\\ x=5\end{array}\right.\end{array}$

Vậy $x\in \left\{\frac{1}{4};5\right\}$