Hấp thụ hết V lít CO2 (đktc) vào 100 ml dung dịch T gồm NaOH 0,2M

* Hướng dẫn giải

$$\begin{gathered} \left\{\begin{array}{l}\frac{1}{2}ddX\stackrel{CaC{l}_2}{\to }\frac{b}{100}mol CaC{O}_3\\ \frac{1}{2}ddX\stackrel{Ca{\left(OH\right)}_2}{\to }\frac{3b}{100}mol CaC{O}_3\end{array}\right. \\ \Rightarrow \left\{\begin{array}{l}\frac{1}{2}ddX chứa \frac{b}{100}mol C{O_3}^{2-}\\ \frac{1}{2}ddX chứa \frac{2b}{100}mol HC{O_3}^{-}\end{array}\right. \\ \left\{\begin{array}{l}BTNT: \frac{1}{2}ddX có n_{Na}=\frac{4b}{100}=0,04\\ NTNT C: n_{C{O}_2}=n_{HC{O_3}^{-}\left(X\right)}+n_{C{O_3}^{2-}\left(X\right)}-n_{C{O_3}^{-}\left(T\right)}\end{array}\right. \\ \Rightarrow \left\{\begin{array}{l}b=1\\ n_{C{O}_2}=0,5\Rightarrow 11,2 lít\end{array}\right. \end{gathered}$$