Tìm x biết ​\(\begin{array}{l} 3\frac{1}{4} - x + \frac{5}{6} = \frac{2}{5} + \frac{4}{3} \end{array}\)

Câu hỏi :

Tìm x biết \(\begin{array}{l} 3\frac{1}{4} - x + \frac{5}{6} = \frac{2}{5} + \frac{4}{3} \end{array}\)

A.  \(x = \frac{{47}}{{20}}\)

B.  \(x = \frac{{17}}{{20}}\)

C.  \(x = \frac{{37}}{{20}}\)

D.  \(x = \frac{{7}}{{20}}\)

* Đáp án

A

* Hướng dẫn giải

 \(\begin{array}{l} 3\frac{1}{4} - x + \frac{5}{6} = \frac{2}{5} + \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = 3\frac{1}{4} + \frac{5}{6} - \frac{2}{5} - \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{13}}{4} + \frac{5}{6} - \frac{2}{5} - \frac{4}{3}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{195}}{{60}} + \frac{{50}}{{60}} - \frac{{24}}{{60}} - \frac{{80}}{{60}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{141}}{{60}}\\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x = \frac{{47}}{{20}} \end{array}\)

Copyright © 2021 HOCTAP247