Tìm x biết ​\(\left|\frac{1}{3} x-\frac{1}{4}\right|=\frac{1}{12}\)

* Hướng dẫn giải

 \(\begin{aligned} &\left|\frac{1}{3} x-\frac{1}{4}\right|=\frac{1}{12} \\ & \frac{1}{3} x-\frac{1}{4}=\frac{1}{12} \quad \text { hoặc } \quad \frac{1}{3} x-\frac{1}{4}=\frac{-1}{12} \\ &\frac{1}{3} x=\frac{1}{12}+\frac{1}{4} \quad \text { hoặc } \quad \frac{1}{3} x=\frac{-1}{12}+\frac{1}{4} \\ & \frac{1}{3} x=\frac{1}{3} \quad \text { hoặc } \quad \frac{1}{3} x=\frac{1}{6} \\ & x=\frac{1}{3}: \frac{1}{3}=1 \quad \text { hoặc } \quad x=\frac{1}{6}: \frac{1}{3}=\frac{1}{2} \end{aligned}\)