A. \(\left\{ \begin{array}{l} x = - 1 + 2t\\ y = 2 - t \end{array} \right.\)
B. \(\left\{ \begin{array}{l} x = t\\ y = 4 + 2t \end{array} \right.\)
C. \(\left\{ \begin{array}{l} x = - 1 + 2t\\ y = 2 + t \end{array} \right.\)
D. \(\left\{ \begin{array}{l} x = 1 + 2t\\ y = 2 - t \end{array} \right.\)
A
\(\begin{array}{l} \left\{ \begin{array}{l} A\left( { - 1;2} \right) \in d\\ {{\vec n}_\Delta } = \left( {2; - 1} \right)\\ d \bot \Delta \end{array} \right.\\ \Rightarrow \left\{ \begin{array}{l} A\left( { - 1;2} \right) \in d\\ {{\vec u}_d} = \left( {2; - 1} \right) \end{array} \right.\\ \Rightarrow d:\left\{ \begin{array}{l} x = - 1 + 2t\\ y = 2 - t \end{array} \right.\left( {t \in R} \right). \end{array}\)
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