Cho sơ đồ chuyển hóa sau: Cr suy ra X suy ra M suy ra Z suy ra T suy ra Y. T và Y lần lượt là?

$$\begin{gathered} Cr\underset{}{\overset{+HCl\left(l\right)}{\to }}CrC{l}_2\underset{}{\overset{+C{l}_2}{\to }}CrC{l}_3\underset{}{\overset{+B{r}_2+KOH}{\to }}{K}_{2}Cr{O}_4 \\ \underset{}{\overset{H_{2}S{O}_4\text{ loãng}}{\to }}{K}_{2}C{r}_2{O}_7\underset{}{\overset{FeS{O}_4+H_{2}S{O}_4}{\to }}C{r}_2{\left(S{O}_4\right)}_3 \end{gathered}$$

1) $Cr+2HC{l}_{\left(l\right)}\underset{}{\overset{}{\to }}CrC{l}_2\left(X\right)+H_2$

2) $2CrC{l}_2+C{l}_2\underset{}{\overset{t°}{\to }}2CrC{l}_3\left(Y\right)$

3) $2CrC{l}_3+3B{r}_2+16KOH\underset{}{\overset{}{\to }}2K_{2}Cr{O}_4\left(Z\right)+6KBr+6KCl+8H_{2}O$

4) $2K_{2}Cr{O}_4+H_{2}S{O}_4\underset{}{\overset{}{\to }}{K}_{2}C{r}_2{O}_7\left(T\right)+K_{2}S{O}_4+H_{2}O$

5) $6FeS{O}_4+K_{2}C{r}_2{O}_7+7H_{2}S{O}_4\underset{}{\overset{}{\to }}3F{e}_2{\left(S{O}_4\right)}_3+C{r}_2{\left(S{O}_4\right)}_3\left(M\right)+K_{2}S{O}_4+7H_{2}O$

Chọn đáp án D.