Tìm x biết rằng \(\begin{aligned} &\text { } 4(x+3)(3 x-2)-3(x-1)(4 x-1)=-27 \end{aligned}\)

* Hướng dẫn giải

 \(\begin{aligned} &\text { } 4(x+3)(3 x-2)-3(x-1)(4 x-1)=-27 \\ &(4 x+12)(3 x-2)-(3 x-3)(4 x-1)=-27 \\ &12 x^{2}-8 x+36 x-24-12 x^{2}+3 x+12 x-3=-27 \\ &43 x-27=-27 \\ &43 x=-27+27 \\ &43 x=0 \\ &x=0 \end{aligned}\)