Tìm x sao cho: \(\left| {\dfrac{{{x^2} - 5x + 4}}{{{x^2} - 4}}} \right| \le 1\)

A \(\left( {2; + \infty } \right)\)

B \(\left( { - 2;0} \right)\)

C \(\left( { - 3; - 2} \right)\)

D \(\left[ {0;\;\frac{8}{5}} \right] \cup \left[ {\frac{5}{2}; + \infty } \right)\)