Viết tọa độ các vecto sau : \(\begin{array}{l}
\vec a = 2\vec i - 3\vec j & & \vec b = \frac{1}{3}\vec i + 5\vec j & \\
\overrightarrow c = 3\overrightarrow i &am...

A \(\begin{array}{l}
\overrightarrow a = \left( {2; - 3} \right) & & \overrightarrow b = \left( {\frac{1}{3};\, - 5} \right)\\
\overrightarrow c = \left( {3;\,\,0} \right) & & \overrightarrow d = \left( {0;\,\,2} \right)
\end{array}\)

B \(\begin{array}{l}
\overrightarrow a = \left( {2; - 3} \right) & & \overrightarrow b = \left( {\frac{1}{3};\,\,\,5} \right)\\
\overrightarrow c = \left( {3;\,\,0} \right) & & \overrightarrow d = \left( {0;\,\,2} \right)
\end{array}\)

C \(\begin{array}{l}
\overrightarrow a = \left( {2; - 3} \right) & & \overrightarrow b = \left( {\frac{1}{3};\,\,\,5} \right)\\
\overrightarrow c = \left( { - 3;\,\,0} \right) & & \overrightarrow d = \left( {0;\,\,2} \right)
\end{array}\)

D \(\begin{array}{l}
\overrightarrow a = \left( {2; - 3} \right) & & \overrightarrow b = \left( {\frac{1}{3};\,\,\,5} \right)\\
\overrightarrow c = \left( {3;\,\,0} \right) & & \overrightarrow d = \left( {0;\, - \,2} \right)
\end{array}\)